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| Geometry - solid figures
solved problems |
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Solid figures, solved problems examples |
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| Example:
An isosceles
triangle, of leg b
= 2
that is inclined to the base at a
= 30°,
rotates around its base
bisector. Find the volume of obtained solid of revolution. |
| Solution: Given
b
= 2 and a
= 30°.
Vsolid
of revolution = ? |
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| Example:
Find the volume of the solid generated by rotating an equilateral triangle
ABC
of the side a
= 2
around the axis
which passes through vertex C parallel to base
AB. |
| Solution: Given
a
= 2.
Vsolid
of revolution = ? |
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| Example:
In a regular square pyramid of height 2
and side of the base 1
inscribed is a cube. The side of
the cube
is? |
| Solution: Given
h
= 2 and
a = 1.
x
= ? |
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| Example:
Height of a cone is 12 and the volume
324p. Find the central angle of the sector to which is
unrolled the side
surface of the cone. |
| Solution: Given
h
= 12 and
V = 324p.
a
= ? |
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| Example:
An isosceles trapezoid
with bases lengths, 3n
and n,
whose base angle is
45°, rotates around
greater base.
Find the volume of the solid of revolution. |
| Solution: Given
bases lengths,
3n
and n,
and base angle 45°.
Vsolid
of revolution = ? |
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| Example:
By rotating the rhomb around its longer diagonal generated is solid whose volume is two times smaller than the
volume of the solid generated by rotating the rhomb around its shorter diagonal. The ratio of diagonals
d1
: d2, (d1
> d2 ),
is? |
| Solution: Given
V1
: V2
= 1
: 2. d1
: d2
= ? |
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| Example:
In a sphere of radius
2
cm inscribed is a cone of the height
3
cm. The ratio of volumes of the
cone
and the sphere is? |
| Solution: Given
R
= 2 cm
and h
= 3 cm.
Vconic
: Vsphere
= ? |
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| Example:
The slant height of a cone is
3 cm
and is inclined to the base of the cone at the angle 60°. The
surface of the
sphere inscribed in the cone is? |
| Solution: Given
s
= 3 cm and
a
= 60°. S
sphere
= ? The cross section through the apex and center of the base of the cone
is the equilateral triangle. |
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| Example:
A channel’s cross section has the form of the isosceles trapezoid of bottom side
2
m and upper parallel side
4
m and altitude
1
m. How much water is in the channel if it is fulfilled to the half of its height? |
| Solution: Given,
c
= 4 m,
a
= 2 m,
h
= 1 m,
and l
= 100 m.
V
= ? |
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| Geometry
and use of trigonometry contents - B |
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