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ALGEBRA
- solved problems |
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Natural
numbers and integers,
rules and properties |
Operations on integers |
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11. |
Add
integers with same signs.
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Solution:
To
add integers having the same sign, keep the same sign and
add the absolute value of each number. |
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12. |
Add
integers with different signs.
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Solution:
To add integers with different
signs, keep the sign of the number with larger absolute value and subtract smaller absolute
value from the larger. |
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13. |
Subtract
given integers:
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Solution:
Subtract an integer by adding its
opposite, |
a) 5 -
7
=
5
+ (-
7)
= -
2,
b)
-
1
-
8
=
-
1
- (
+ 8)
= - 1+
(-
8)
= -
9, |
c) 4 -
( -
3)
=
4
+ (
+
3)
= 7,
d)
-
5
- (-
9)
=
-
5
+
(+ 9)
= -
5+
9
= 4. |
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14. |
The use
of parentheses:
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Solution:
Evaluate given expressions, |
a) (-
5
+ 3)
+ 6
= -
5
+ 3
+ 6 = 4,
b)
-
7
+ (-
3
+ 8)
= -
7
-
3
+ 8 = -
2, |
c) 6 -
( 5 -
12)
= 6 -
5
+ 12 = 13,
d)
- (-
2
+
7)
+ 3
= 2
-
7
+ 3 = -
2. |
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Multiplication and
division of integers |
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15. |
Multiply
given integers:
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Solution:
a) 7 · 0 =
0,
b)
(-
1)
· 18 = -
18, |
c) (-
3)
· (-
4) = 12,
d)
3
· (-
4) = -12. |
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16. |
Multiply
given integers:
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Solution:
a) (-
3
+ 5)
· 6
= (-
3)
· 6
+
5 · 6
= -
18
+ 30
= 12, |
b) ( 7
-
4)
· (-
3)
= 7 ·
(-
3)
-
4 · (-
3)
= -
21+
12 =
-
9, |
c) (-
5
)
· 3
+ 2
· 3
= (-
5
+ 2)
· 3
= (-
3) ·
3 =
-
9, |
d) 9 · (-
6)
- 2
· (-
6)
= (9 -
2)
· (-
6)
= 7 ·
(-
6) =
-
42. |
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Solution:
a) (-
7
+ 4)
· (-
2)
= (-
7)
· (-
2)
+ 4
· (-
2)
= 14 -
8
= 6
or (-
3) ·
(-
2) = 6, |
b) -
9 · a
+ 5
· a
= (-
9
+
5)
· a
= -
4a,
c)
3 ·
(1 -
a)
+ 5
= 3
-
3
· a
+ 5
= 8
-
3a. |
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18. |
Divide
given integers:
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Solution:
a) 0
¸ 5
= 0,
b)
-
3
¸
1
= -
3, |
c) -
28
¸
(-
4) =
28 ¸ 4
= 7,
d) 45
¸
(-
15) =
-
45 ¸ 15
= -
3. |
If both the dividend and divisor signs are the same the quotient will
be positive, if they are different, the quotient will be negative.
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19. |
Divide
given integers:
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Solution:
a) (36 ¸ 6)
¸2
= 6
¸ 2
= 3,
while b)
36 ¸(6
¸ 2)=
36 ¸ 3
= 12, |
c) 18 ¸
6 ¸
3
=
3 ¸ 3
= 1,
while d) 18
¸(6
¸ 3)=
18 ¸ 2
= 9. |
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Order
of operations - parenthesis as grouping symbols
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Solution:
a) -
8 -
3 ·
(-
4)
+ 15
¸ (-
5) =
-
8 -
(-
12)
+
(-
3) =
-
8
+ 12
-
3
= 1. |
When expressions have more than one operation, we have to follow
rules for the order of operations.
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First do all multiplication and
division operations working from left to right. Next do all addition
and subtraction. |
b) -
3
+ 2
· [-
2 -
3 ·
(-
4 ¸
2
+ 1)]
=
-
3 + 2
· [-
2 -
3 ·
(-
2 +
1)] |
=
-
3
+ 2
· [-
2 -
3 ·
(-
1)]
=
-
3
+ 2
· [-
2 +
3]
=
-
3
+ 2
=
-
1. |
We often use grouping symbols, like parentheses, to help us
organize complicated expressions into simpler ones. |
Do operations
in parentheses and other grouping symbols first. If there are grouping
symbols within other grouping symbols do the innermost first. |
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The
integer prime-factorization
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21. |
Find the prime factors of
350.
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Solution:
The
sequence of prime numbers begins 2, 3, 5, 7, 11, 13, 17, 19, 23, ... |
Every positive integer greater than 1 can be factored as
a product of prime numbers.
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Given a number
n divide by the first prime from the list of primes, if it does not divide
cleanly, divide n by the next prime, and so on.
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Thus, the prime factors of 350
= 2
· 5
· 5
· 7.
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350
| 2 |
175
| 5 |
35
| 5 |
7 | 7 |
1
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The
greatest common divisor (GCD) |
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22. |
Find the greatest common divisor of
72 and 90.
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Solution:
The greatest common divisor of two integers is the largest integer
that divides both numbers. |
The greatest common divisor can be computed by determining the prime
factors of the two numbers and comparing the factors,
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72
= 2
· 2
· 2
· 3
· 3,
90 = 2
· 3
· 3
· 5,
=>
GCD(72, 90) = 2
· 3
· 3
= 18. |
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The
least common multiple (LCM)
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23. |
Find the least
common multiple or
LCM of, 24, 54 and 60.
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Solution:
A common multiple is a number that is a multiple of two or more
numbers. |
The least common multiple of two integers a and
b
is the smallest positive integer that is a multiple of both
a and
b. To
find the least common multiple of two numbers: |
- first list the prime
factors of each number, then
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- multiply each factor the greatest
number of times it occurs in either number. |
If the same factor occurs more than once in both numbers, multiply the factor the greatest
number of times it occurs. |
Thus,
the prime factors: 24 = 2
· 2
· 2
· 3,
54 = 2
· 3
· 3
· 3,
60 = 2
· 2
· 3
· 5,
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=>
LCM(24, 54, 60) = 2
· 2
· 2
· 3
· 3
· 3
· 5 = 1080. |
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Operations on real
numbers |
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24. |
Add or
subtract given real numbers:
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Solution:
a)
−7 − 4 =
− 7 + (−
4) =
− 11,
b )
+ 3 − 9 =
3 + (−
9) = −
6, |
c)
5 − (−
6) = 5
+ (+
6) = 11,
d )
−3 − (−
9) =
−3 + 9
= 6,
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e)
0.5 − 1.5 = 0.5
+ (−
1.5) = −
1,
f )
−1.5 − 0.25 =
−1.5 + (−
0.25) = −1.75.
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25. |
Multiply
or divide given real numbers:
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Solution:
a)
−7 · (−
4)
= 28,
b)
3 · (−
9)
= −
27,
c)
− 6 ·
0.1 = −
0.6, |
d)
6 ¸
(−
0.1) = 6
· (−
10)
= − 60,
e) −
8 ¸ (−
0.125) =
− 8 · (−
1000/125)
= 64 |
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