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ALGEBRA
- solved problems
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Ratios and proportions
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Ratios and proportion properties
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99. |
Write a proportion by given ratios.
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Solution: |
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9
: 6 = 3/2
and, 21
: 14 = 3/2,
follows,
9 :
6 = 21 : 14. |
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A proportion is
a statement of the equality of two ratios. If the fractions both reduce
to the same value, the proportion is true.
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100. |
Use ratios and proportion properties to rewrite
given expressions.
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Solutions: |
Since, |
a
:
b =
(a · c)
:
(b ·
c) |
then
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a) |
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and |
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b) |
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Direct and inverse proportion
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101. |
A lift reaches the third floor in seven seconds. When will reach
the 18th floor?
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Solution: |
Given quantities make the proportion |
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x1
:
y1 =
x2
:
y2. |
That
is, |
3
:
7 =
18 :
x |
=> |
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seconds. |
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We could obtain the same result by setting up the corresponding
values of the proportional quantities in a table where arrows show the sequence of the terms of the proportion. |
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¯ |
3rd
floor |
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¯ |
7
sec. |
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18th
floor |
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x
sec. |
or |
3
:
18 = 7 :
x |
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=> |
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seconds. |
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102. |
To
the central angle a = 30°, of a circle of radius
r, corresponds
the arc length equal
p/6
r.
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What arc length corresponds to the
central angle a = 320°?
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103. |
If 12 workers can do a job in 15 hours, then how many workers
would be needed to do the job in 9
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hours?
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Solution: |
It’s obvious that more workers will do a job in shorter time. That
means, the time it takes to do |
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the job is inversely proportional to the
number of workers.
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Therefore, use the proportion or set up the
table where the corresponding values make the colons and the arrows show the sequence of the terms of the proportion.
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ß |
12
workers |
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Ý |
15
hours |
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Thus, |
x
workers |
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9
hours |
or |
12
:
x =
9 :
15 |
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=> |
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workers. |
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104. |
A distance
d
from place A to place B a car covers in 75 minutes
traveling at the rate of 120 km/h.
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At what rate it should drive so that
it will travel the same distance in 60 minutes. |
Solution: |
By driving two times
faster, the same distance it will cover in half less time. |
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Since, rate
r and time
t are inversely proportional quantities use the proportion
x1
:
x2 =
y2
:
y1. |
As the quantities we are comparing must always
be measured in the same units, we’ll convert minutes to hours,
so 75 min =
75
min
· 1hour
/ 60
min =
1.25
h.
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ß |
1.25
h |
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Ý |
120
km/h |
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Thus, |
1
h |
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x
km/h |
or |
1.25
:
1
= x :
120 |
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=> |
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km/h. |
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Percent
or percentage
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Percent, decimal number and
fraction conversions
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105. |
As appropriate, given
values convert
to, a percent, a decimal number and a fraction.
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Basic percent formulas |
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Solution: |
From the proportion, |
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part
: base (whole) = rate : 100
or y
: x =
p
: 100 |
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we calculate,
the part or amount y,
the rate p
and the base value x. |
Since
given, x =
80,
p%
= 25%,
y =
? |
Therefore, |
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107. |
What percent of 80 is 20?
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Solution: |
Given,
y =
20,
x =
80,
p%
=
? |
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Therefore, |
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108. |
What is the base value if
25% of it is 20?
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Solution: |
Given,
p%
= p/100 = 25%,
y =
20,
x =
? |
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Therefore, |
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The base value |
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therefore |
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represents
1% of the base value. |
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Percent
increase or decrease,
base (x),
amount (y),
percent (p) |
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109. |
In the price of $33 included is tax of 10%.
What is net price?
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Solution: |
From the proportion, |
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x
: 100
=
( x
±
y )
: ( 100
±
p) |
then, |
y
: p
=
( x
±
y )
: ( 100
±
p) |
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where
x
±
y denotes original or base value x increased or decreased by amount
y |
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Since
given, x
+
y =
33 ,
p%
= 10%,
x
=
? |
Therefore, |
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110. |
Price reduced by 20% amounts
to $320. How much is reduced?
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Solution:
Given, x
-
y =
320 ,
p%
= 20%,
y
=
? |
Therefore, |
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problems contents |
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