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Integral
calculus |
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The
indefinite integral |
Integration by parts rule |
The indefinite integrals
containing quadratic polynomial (trinomial)
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The indefinite integrals
containing quadratic polynomial, examples
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Integration
by parts rule
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The rule for differentiating the
product of two differentiable functions leads to the integration
by parts formula.
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Let f
(x)
and g
(x)
are differentiable functions, then the product rule gives
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[ f
(x) g (x)]'
= f (x)
g (x)' + g (x)
f ' (x),
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by
integrating both sides |
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Since the integral of the derivative
of a function is the function itself, then
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and by rearranging obtained is
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the integration by parts
formula.
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By substituting
u = f
(x) and
v
= g (x)
then, du =
f ' (x)
dx and dv
= g' (x)
dx, so that
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To apply the above formula, the
integrand of a given integral should represent the product of one
function and the differential of the other.
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The selection of the function
u and the differential dv
should simplify the
evaluation of the remaining integral.
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In some cases it will be necessary to
apply the integration by parts repeatedly to obtain a simpler
integral.
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Use similar methods to solve this
integral as in the preceding example. Hence,
the solutions depend on the
sign of the leading
coefficient
a
and the sign or the value of the vertical translation y0.
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Let solve given integral by separating
the derivative of the quadratic polynomial in the numerator.
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Use the substitution mx + n = 1/ t .
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The integrand function to be real, the
quadratic polynomial must be positive, therefore
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a
) if a
> 0 and
y0
is not
0 then
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see the solutions of the integrals,
example 31 and 36. By using above substitutions
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Note that the sign of the vertical
translation y0
affects the solution, i.e.,
changes the sign of its second term.
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b
) if a
< 0 and
y0
>
0 then
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see the solution of the integral
example 8 above. After applying the substitutions
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Functions
contents G |
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