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Ellipse
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The parametric equations of the ellipse |
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Equation of a translated ellipse
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Equations of the ellipse examples |
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| The parametric equations of the
ellipse |
| Equation of the ellipse in the explicit form |
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can help us to explain another construction |
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the ellipse. So, in the coordinate system draw two concentric circles of radii equal to lengths of the semi axes a and b, with the center at the origin as shows the figure. |
An arbitrary chosen line through the origin intersects the
circle of the radius a
at the point R
and the circle of radius b
at M.
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Then, the parallel line with the major axis through M
intersects the parallel line with the minor axis through
R, at
a point P(x,
y) of the ellipse.
Proof, |
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the figure, OS
= x,
PS
= y
and |
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as the triangles
OMN
and ORS
are similar, then
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OM
: OR
= MN
: RS
or b
: a
= PS
: RS,
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that |
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| It proves that the point
P(x,
y) obtained by the construction
lies on the ellipse. This way, using the figure, we also derive |
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parametric equations of
the ellipse |
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where the parameter
t
is an angle 0
<
t
<
2p. |
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| By dividing the first parametric equation by
a
and the second by b, then square and add them, obtained is
standard equation of the ellipse. |
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| Equation of a translated ellipse
-the ellipse with the center at
(x0,
y0)
and the major axis parallel to the x-axis. |
| The equation of an ellipse that is translated from its standard position can be obtained by replacing
x
by x0 |
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y by
y0 in its standard equation, |
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| The above equation can be rewritten into
Ax2
+ By2 + Cx + Dy + E = 0. |
| Every equation of that form represents
an ellipse if A
not equal
B
and A ·
B > 0 that is, if the square terms have unequal coefficients, but the same
signs. |
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| Equations
of the ellipse examples |
| Example:
Given is equation of the ellipse
9x2
+ 25y2 = 225, find the lengths of semi-major and
semi-minor axes, coordinates of the foci, the eccentricity and the length of the
semi-latus rectum. |
| Solution: From the standard equation |
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we can find the semi-axes
lengths dividing the given |
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| equation by
225, |
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coordinates of the
foci F1(-c, 0) and
F2(
c, 0),
since
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| Example:
From given quantities of an ellipse determine remaining unknown quantities and write equation
of the ellipse, |
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| Solution:
a) Using |
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the semi-minor axis |
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linear eccentricity |
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semi latus rectum |
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and
the equation of the ellipse |
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| the eccentricity |
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and
the equation of the ellipse |
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semi latus rectum |
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and
the equation of the ellipse |
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d) unknown quantities expressed through given values, |
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| Example:
Find the equation of
the ellipse whose focus is F2(6,
0) and which passes through the point
A(5Ö3,
4). |
| Solution:
Coordinates of the point
A(5Ö3,
4) must satisfy equation of the ellipse, therefore |
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thus,
the equation of the ellipse |
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| Example:
Write equation of the ellipse passing through points
A(-4,
2) and B(8,
1). |
| Solution:
Given points must satisfy equation of the ellipse, so |
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| Therefore,
the equation of the ellipse |
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or
x2
+ 16y2 = 80. |
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| Example:
Given is equation of the ellipse
4x2
+ 9y2
+ 24x -18y
+ 9 =
0,
find its center S(x0,
y0),
the semi-axes and intersections of the ellipse with the coordinate axes. |
| Solution: Coordinates of the center and the semi-axes are shown
in the equation of the translated ellipse, |
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| Rewrite the given equation to that
form, |
| 4(x2
+ 6x)
+ 9(y2 -
2y)
+ 9 = 0 |
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4[(x + 3)2 -
9] +
9[(y -1)2
-1]
+ 9 = 0
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4(x + 3)2
+ 9(y -1)2
= 36
or
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therefore,
S(-3,
1),
a = 3 and
b = 2.
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Intersections of the ellipse and the
x-axis
we obtain by setting y =
0 into the equation of the ellipse, thus
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| 4x2
+ 24x + 9 =
0,
x1,2 = -3
± 3Ö3/2, |
| and intersections of the ellipse
with the y-axis by
setting x
= 0, =>
9y2
-18y
+ 9 =
0,
y1,2 = 1. |
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