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Conic
Sections |
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Parabola
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Transformation of the equation of a parabola
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Equation of a translated parabola - the standard form
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The parabola whose axis
of symmetry is parallel to the y-axis |
Equations of the parabola
written in the general form |
Parabola, examples
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Transformation of the equation of a parabola
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The equation
y2 = 2px,
p < 0
represents the parabola opens to the left since must be y2
> 0. Its axis of
symmetry is the x-axis. |
If variables
x and
y change the role obtained is the parabola whose axis of
symmetry is y-axis.
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For
p >
0
the parabola opens up, if
p <
0
the parabola opens down as shows
the below figure. |
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This parabola we often write
y = ax2,
where
a = 1/(2p) , with the focus at
F(0,
1/(4a)) and the directrix |
y =
-1/(4a).
This parabola is a function since a vertical line crosses its graph at only one point.
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Equation of a translated parabola - the standard form
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By parallel shifting of the parabola
y2 = 2px in the direction of the coordinate axes the vertex of the parabola
can be brought at a point A(x0, y0) while coordinates
x
and y of every point of the parabola changes by the |
value of the
translations x0 and
y0, so that equation of the translated
parabola is
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If p >
0
the parabola
opens to the right and if p
< 0
the
parabola opens to the left.
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If the focal parameter
p = 2a
then the above equation
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becomes,
(y
-
y0)2 =
4a(x
-
x0).
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The translated parabola with the axis parallel to the
x-axis
can also be written as
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x =
ay2
+ by
+ c.
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The parabola whose axis of symmetry is parallel to the y-axis |
By translating the parabola
x2 = 2py
its vertex is moved from the origin to the point A(x0, y0)
so that its equation
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transforms to
(x
-
x0)2 = 2p(y
-
y0).
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The axis of symmetry of this parabola is parallel to the
y-axis.
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As we already
mentioned, this parabola is a function that we usually
write
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y = ax2
+ bx + c
or y
-
y0 =
a(x
-
x0)2, |
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where |
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This parabola opens up if
a >
0 and opens down if
a < 0.
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Equations of the parabola written in the general form |
a) the axis of the parabola parallel to the
x-axis
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b) the axis of the parabola parallel to the
y-axis |
Ay2
+ Bx + Cy +
D =
0, A and
B not
0, |
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Ax2
+ Bx + Cy +
D =
0, A and
C not 0 |
or x =
ay2
+ by
+ c,
a not 0. |
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or
y =
ax2
+ bx
+ c,
a not 0. |
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Note
that the parabola has equation that contains only one squared term. |
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Parabola,
examples |
Example:
Write equation of the parabola
y2 = 2px
passing through the point P(-4,
4) and find the focus,
the equation of the directrix and draw its graph. |
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Solution:
The coordinates of the point P
must satisfy the equation of the parabola
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P(-4,
4)
=>
y2 =
2px
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42 = 2p(-4)
=> p =
-2
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thus, the
equation of the parabola y2 =
-4x.
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The coordinate
of the focus,
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since F(p/2,
0) then
F(-1,
0).
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The equation of the directrix,
as x =
- p/2,
x =
1.
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Example:
Find the vertex, the focus and the equation of the directrix and draw the graph of the parabola |
y =
-x2
+ 6x -
7. |
Solution:
Rewrite
the equation of the parabola in the translatable form
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(x
-
x0)2 = 2p(y
-
y0) or
y
-
y0 = a(x
-
x0)2
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so, y =
-x2
+ 6x -
7
=> y =
-(x2
-
6x) -
7
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y =
-[(x
-
3)2
-
9] -
7
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y
-
y0 = a(x
-
x0)2,
y
-
2 = -(x
-
3)2,
a
= -1.
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The vertex of the parabola
A(x0, y0),
or
A(3, 2).
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The focus
F(x0,
y0 + 1/(4a)),
or
F(3,
7/4).
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The equation of the directrix,
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y =
y0 -
1/(4a),
y = 2 +
1/4 or
y =
9/4.
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College
algebra contents E |
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