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| Trigonometry |
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Values of
trigonometric functions of arcs p/6, p/4 and p/3 |
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The values of the trigonometric functions of arcs that are multipliers of
30°
(p/6)
and 45°
(p/4) |
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Values of
trigonometric functions of arcs
p/6, p/4
and
p/3
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The given arcs are, one twelfth, one eighth and one sixth of the circumference
2p
of the unit circle so the
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coordinates of terminal points of the arcs are the elements of the equilateral triangle with the side
a = 1
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(Fig.a, c) and the sides of the square with diagonal
d = 1, (Fig.
b).
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The values of the trigonometric functions of arcs that are multipliers of
30°
(p/6)
and 45°
(p/4)
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| Example:
Calculate, sin
3p/2
· cos(-
p)
+ tan 5p/4.
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| Solution: sin
3p/2
· cos(-
p)
+ tan 5p/4
= -
1 · (-
1) + tan (p
+ p/4)
= 1 + tan p/4
= 1 + 1 = 2. |
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| Example:
Calculate, |
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Solution:
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Example:
Prove the identity,
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cos2 p/3
· sin (p/2
-
x) -
cos (p
-
x)
· cos2 p/6
= tan (p/2 +
x)
· sin (2p
-
x).
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Solution:
Since sin
(p/2
-
x) = cos
x,
cos (p
-
x) = -
cos
x, tan (p/2 +
x) = -
cot
x
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and sin
(2p
-
x) = -
sin x
then,
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(cos p/3)2
· cos
x -
(-
cos
x)
· (cos p/6)2
= -
cot
x
· (-
sin x),
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(1/2)2
· cos
x + (Ö3/2)2
· cos
x = (cos
x/sin x)
· sin x
=> cos
x = cos
x.
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Example:
Prove the identity,
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cot2 (p +
x)
· cos2 (p/2 +
x) + sin (-
x) · sin (p +
x) = tan (2p
-
x) · cot (-
x).
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Solution:
[cot (p +
x)]2
· [cos (p/2 +
x)]2 +
(-
sin x)
· sin (p +
x) = (-
tan x)
· (-
cot x),
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(cot
x)2
· (-
sin x)2
+ (-
sin x) · (-
sin x) = (sin x/cos
x)
· (cos
x/sin x)
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cos2
x + sin2
x = (sin x/cos
x)
· (cos
x/sin x) = 1.
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| Pre-calculus contents
A |
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